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Acute Triangle -- from Wolfram MathWorld
https://mathworld.wolfram.com/topics/SpecialTriangles.html
WEB2 days ago · From the law of cosines, for a triangle with side lengths a, b, and c, cosC=(a^2+b^2-c^2)/(2ab), with C the angle opposite side C. For an angle to be acute, cosC>0. Therefore, an acute triangle satisfies a^2+b^2>c^2, b^2+c^2>a^2, and c^2+a^2>b^2. The smallest number of acute triangles into which an arbitrary...
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